The argements are compared using the following rules:ġ) If any argument is NULL, the result is NULL, No comparison is neededĢ) If all arguments are integer-valued, ther are eompared as integers.ģ) If at least one areuments is double precision, they are compared as double-precision values. With two or more arguments, returns the smallest(minimum-valued) argument. If expr is NULL, ISNULL() returns 1, otherwise it returns 0 Mysql> SELECT 1 IS NULL, 0 IS NULL, NULL IS NULL The arguments are compared using the same rules as for LEAST(): With two or more areuments, returns the largest(maximim-values) argument. Mysql> SELECT COALESCE(NULL, NULL, NULL) If expris grater than or equal to minand expris less than or equal to max, BETWEENreturns 1, otherwise it return 0, This is equivalent to the expression ( min SELECT COALESCE(NULL, 1) and 0 rather than NULL if one operand is NULL. This operator performs an equality comparison like the = operator, but returns 1 rather than NULL if both operands are NULL. LEAST() and GREATEST()are examples of such functions.īy default, string comparisons are not case-sensitve and use the current character set. Some of the functions in this section return values other than 1(TRUE), 0(FALSE), or NULL. String are automatically converted to numbers and numbers to string as necessary. These operations work for both numbers and strings. Whether a value is niot within a set of valuesĬomparison operations retult in a value of 1(TRUE), 0(FALSE), or NULL. Whether a value is not within a range of values Return the index of the argument that is less than the first argument Whether a value is within a set of values The LEFT JOINs only have to do 5 probes each, not a million.Whether a value is within a range of values The subquery is doing less work since it is touching 2 tables (vs 4). If so, then use that as a subquery, a la FROM (that-select) and LEFT JOIN to the other two tables to get the rest of the info. (INNER and OUTER add nothing.)įirst, see if this gives the correct information (albeit incomplet info): SELECT e.sid, e.cid, COUNT(*) AS total The two SELECTs are likely to be identical order across JOIN does not matter. Since there are a million rows, it will take time. Your query inherently must do a full table scan in order to get the "total" upon which you do the ORDER BY. You seem to be working with IPv4 IP addresses. PLEASE use SHOW CREATE TABLE DESCRIBE is not descriptive enough. I also just noticed you have a.sid and a.ean, what table has an alias of a ? (p.sid = a.sid AND p.preisliste = a.sid AND p.ean = a.ean) LEFT JOIN sellerList AS s ON s.sid = b.sid AND s.pass = b.pass If you actually want the query to be small without hardcoding every value just write the code with a more straightforward LEFT JOIN setup SELECT p.sid, ifnull(p.pricelist,"BASE"), count(*) AS recs FROM buyerList AS b If it is the desired query, execute it PREPARE sql FROM sql using PREPARE sql SELECT GROUP_CONCAT(CONCAT('(p.sid = a.sid AND p.preisliste = ',sid,' AND p.ean = a.ean AND p.iln = ',pricelist',)') SEPARATOR ' OR ') Try assembling the SQL statement like this: = 'SELECT sid, ifnull(pricelist,"BASE"), count(*) AS recs FROM buyerList AS b = JOIN sellerList AS s ON s.sid = b.sid AND s.pass = b.pass = JOIN pricelists p ON ') With regard to what you want to accomplish, you do not need a stored procedure. MySQL does not facilitate such a mechanism. Where campaign_center.campaign_id != 'Demo'įrom the question, it looks like what you have written quasi-resembles what Oracle calls an anonymous code block. Where campaign_center.campaign_id = 'Demo'īut again when i am trying to find those company who's campaign_id is not 'Demo' it doesn't give correct output: select center.id, pany_name When I execute this query it's working perfectly: (To find center_id and company name who's campaignid is 'Demo') select center.id, pany_name 1st Table : center (2 columns) +-+Ģnd Table : campaign_center (3 columns) +-+
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